In the structure CH_3 - C^2H(C^1H_3) - C^3H_2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Homolytic bond dissociation energy $(BDE)$ is inversely proportional to the stability of the free radical formed after the bond breaks. Stability

Vedclass · Accepted Answer

$C_1-H > C_4-H > C_3-H > C_2-H$

Vedclass · Answer

(D) Homolytic bond dissociation energy $(BDE)$ is inversely proportional to the stability of the free radical formed after the bond breaks. Stability of free radicals follows the order: $3^\circ > 2^\circ > 1^\circ$. In the given molecule (isopentane): $1.$ $C_2-H$ is a $3^\circ$ bond (forms a $3^\circ$ radical,which is the most stable). $2.$ $C_3-H$ is a $2^\circ$ bond (forms a $2^\circ$ radical). $3.$ $C_1-H$ and $C_4-H$ are $1^\circ$ bonds (form $1^\circ$ radicals,which are the least stable). Among the $1^\circ$ bonds,the $C_4$ radical is slightly more stable than the $C_1$ radical because $C_4$ has two $\beta$-hydrogens available for hyperconjugation,while $C_1$ has only one. Therefore,the $BDE$ order is: $C_1-H > C_4-H > C_3-H > C_2-H$.

In the structure $CH_3 - C^2H(C^1H_3) - C^3H_2 - C^4H_3$,the order of homolytic bond dissociation energy for $C_1-H, C_2-H, C_3-H$ and $C_4-H$ is:

Similar Questions

The $C-H$ bond distance is longest in

$4.3 \ g$ of an alkane is burnt in sufficient oxygen. The $CO_2$ formed reacts completely with $300 \ mL, 2 \ N \ NaOH$ solution producing $Na_2CO_3$. The alkane is:

The octane number $100$ is assigned to .............

For complete combustion of $10 \ L$ of alkane,the volume of oxygen required is $50 \ L$. Identify the alkane.

The most volatile alkane is

Vedclass Test Series

Exam Paper Generator

Online Exam Module